1 - 1
2 - 3
3 - 6
4 - 10
5 - 15
6 - 21
7 - 28
8 - 36
9 - 45
b) As n gets larger, the value that comes out is the previous value added to n. The pattern is very uniform and easy to figure out, to me at least.
c) I think there is a formula, but I do not think I am simply smart enough to think of it haha. All I know is to get another number, you add the previous number to the n integer you are trying to find at the moment, if that makes sense? I don't know.
d) Again, I do believe there is a formula and exists, because I think we learned this in Probability/Statistics last year and/or Advanced Math. I think Jordan is good with this kind of stuff...I supposed you would ask something like this Jordan, thanks. But I really don't remember anything at the moment.
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