Stephen's blog 3?

Question 1:

a) n=3, s=2+4+6=12

n=4, s=2+4+6+8=20

n=5, s=2+4+6+8+10=30

n=6, s=2+4+6+8+10+12=42

and so on...

b) for last week, all that basically happens is you add the previous n. As n gets larger, the value that comes out is the previous value added to n. The pattern is very uniform and easy to figure out, to me at least.

c) It makes perfect logical sense because when you add n or do anything with it basically, you're using the same numbers, therefore getting similar numbers as outputs.

Question 2:

a) n=1, s=1=1

n=2, s=1+3=4

n=3, s=1+3+5=9

n=4, s=1+3+5+7=16

n=5, s=1+3+5+7+9=25

n=6, s=1+3+5+7+9+11=36

n=7, s=1+3+5+7+9+11+13=49

n=8, s=1+3+5+7+9+11+13+15=64

n=9, s=1+3+5+7+9+11+13+15+17=81

b) The obvious pattern that arises is that the sum of n is n^2, which is an obvious formula.

c) This holds true for n because every time you add these odd integers of n itself, you will get n^2. All of these numbers are related. No matter what you plug in, you will always get that number multiplied by itself.