Post # 4

soo..Prime factorization of 1332:
13322 * 6662 * 9 * 742 * 3 * 3 * 2 * 372^2 * 3^2 * 37

GCD and LCM of 240 and 840.
240 10 * 245 *
GCD= 2^3 * 3 * 5 = 120
LCM = 2^4 * 3 * 5 * 7 = 1680

If you divide both prime numbers starting with the smallest prime number and continuing to increase the number, you will realize that 19133 isn't prime; but 103 is.

The biggest number that thirteen is divisable by is 480316; since that is nine numbers less than a number divisable by it, the remainder is nine.

and that's about all i can do on this blog.
i'm not sure if i should know how to do this stuff..
or look it up. or maybe i'm just not thinkging properly.

Connor's blog 4

(Please show your work (briefly))
Question 1:
What is the prime factorization of 1332?
Question 2:
What is the gcd and lcm of 240 and 840?
Question 3:
Is 133 prime? What about 103? How did you find out that it is/is not (without looking it up.)
Question 4:
What is the remainder when 4803925 is divided by 2? What is it when it is divided by 3? By 5? By 13?
How did you figure each of these out?

Q1: 1332
2 x 666 ZOMG 666, THE NUMBER OF THE BEAST :O
2 x 333
3 x 111
3 x 37
2^2 x 3^2 x 37

Q2: GCD and LCM 240 and 840
GCD: 840-240=600
600- 240=360
360-240=120
240-120=120
LCM: 2^4 x 3 x 5 x 7 = 1680

Q3: 133 isn't prime; because I'm good like that and I checked it with numberrsss
103 is prime; same as the above reason

Q4: 4803925/2 = 2401962.5
4803925/3 = 1601308.3(repeating)
4803925/5 = 960785.0
4803925/13 = 369532.692
how did I figure them out? I used a calculator of course

Connor's blog 4

(Please show your work (briefly))
Question 1:
What is the prime factorization of 1332?
Question 2:
What is the gcd and lcm of 240 and 840?
Question 3:
Is 133 prime? What about 103? How did you find out that it is/is not (without looking it up.)
Question 4:
What is the remainder when 4803925 is divided by 2? What is it when it is divided by 3? By 5? By 13?
How did you figure each of these out?

Q1: 1332
2 x 666 ZOMG 666, THE NUMBER OF THE BEAST :O
2 x 333
3 x 111
3 x 37
2^2 x 3^2 x 37

Q2: GCD and LCM 240 and 840
GCD: 840-240=600
600- 240=360
360-240=120
240-120=120
LCM: 2^4 x 3 x 5 x 7 = 1680

Q3: 133 isn't prime; because I'm good like that and I checked it with numberrsss
103 is prime; same as the above reason

Q4: 4803925/2 = 2401962.5
4803925/3 = 1601308.3(repeating)
4803925/5 = 960785.0
4803925/13 = 369532.692
how did I figure them out? I used a calculator of course

Jeffers.!

1. Find the prime factorization of 1332
2 666
2 333
3 111
3 37
2^2 * 3^2 *37

2. GCD and LCM of 240 and 840
2 120
2 60
2 50
2 15
3 5
2^4 * 3*15

3. 840
2 420
2 210
2 105
5 21
3 7
2^3*5*7
GCD=2^3 * 3*5=120
LCM=2^4* 3*5*7= 1680

4.are 133 or 103 prime?
133 is not prime, it is divisible by 7 and 19.
103 is prime b/c it has no other factors beside 1 and itself.
You use a factor tree to solve this out, if you are unable to, then its prime

5. 4803925/2
I solved this by using loooong division.
2=1(odd number)
3=1(number adds to give you 31,one over 30 a multiple of 3)
5=0(goes into number evenly because 5 can go into any number evenly that ends in 0 or 5.)
13=9

Justin 4

1. find the prime factorization of 1332

3 444
4 111
3 37
2^2x3^2x37

2. find the gcd and lcm of 240 and 840

240

3 80
8 10
2 5
2^4x3x5

840

7 120
5 24
3 8
2^3x3x5x7

GCD=2^3x3x5=120
LCM=2^4x3x5x7=1680

3. are 103 and 133 prime?
133 is not
103 is
divide by prime numbers to find out

4.remainder when 4083925 is diveded by 2, 3, 5, and 13
a. divide by 2 R=1
b. divide by 3 R=1 the digits add up to 31
c. divide by 5 R=0
d. divide by 13 R=9

Heather's #4

1.) Prime Factorization of 1332:
1332
2(666)
2(333)
3(111)
3(37)
= 2^3 x 3^3 x 7

2.) GCD (240, 840)
*Prime factorizations:
240:
2(120)
2(60)
2(30)
2(15)
3(5)
=2^4 x 3 x 5

840:
2(420)
2(210)
2(105)
3(35)
5(7)
= 2^3 x 3 x 5 x 7
*To find the GCD, you look at the prime factorization of 240 and 840. You cross out the numbers they do not have in common (so for this one you would rule out 7). Then you multiply the numbers in common that have the least exponent.
*So you would take 2^3 x 3 x 5
GCD = 120

LCM (240, 840)
*For this you still use the prime factorization of both numbers but instead you multiply each number there with the highest exponent (and you include every number present, whether they have it in common or not)
*So you would get 2^4 x 3 x 5 x 7
LCM = 1680

3.) Is 133 prime? NO...Is 103 prime? YES!
*I simply used divisibility rules. And 133 is composite because I found that 7 can go into it evenly, whereas nothing can go into 103.

4.) Remainders when 4803925...
*is divided by 2 -- remainder is 1
*divided by 3 -- remainder is also 1
*divided by 5 -- there is NO remainder. 5 goes in evenly (divisibility rules say that 5 can go into any number that ends in a 5 or zero evenly)
*divided by 13 -- remainder is 9
**I found these out simply by dividing 4803925 by every number given, except 5.

Prompt 4 from Ryan

Prime factorization of 1332:
1332
2 * 666
2 * 9 * 74
2 * 3 * 3 * 2 * 37
2^2 * 3^2 * 37

GCD and LCM of 240 and 840.
240
10 * 24
5 * 2 * 2 * 12
5 * 2 * 2 * 6 * 2
5 * 2 * 2 * 3 * 2 * 2
2^4 * 3 * 5

840
10 * 84
5 * 2 * 2 * 42
5 * 2 * 2 * 2 * 21
5 * 2 * 2 * 2 * 3 * 7
2^3 * 3 * 5 * 7

GCD = 2^3 * 3 * 5 = 120
LCM = 2^4 * 3 * 5 * 7 = 1680

Are 133 or 103 prime?
You have to divide both by prime numbers starting with 2 and keep going until the number you are dividing by is bigger than the quotient.
133/7 = 19
133 is not prime
103 is prime.

R when 4803925 is divided by 2, 3, 5, and 13.
By 2, it will be R1 because it is an odd number.
By 3, it will be R1 because the number add to give you 31, which is one over a multiple of 3.
By 5, it will be R0 because 5 goes into the number evenly.
By 13, I found the biggest number 13 could go in to less than 4803925, and I got 480316. Since 480316 is 9 less than 4803925 then the remander is 9.